90 lines
3.0 KiB
Python
90 lines
3.0 KiB
Python
|
""" Exercicio 09.
|
||
|
|
Analise e execute o programa dates.py. Faça as correçoes indicadas abaixo.
|
||
|
|
|
||
|
|
a. A funçao isLeapYear deveria indicar quando um ano é bissexto, mas esta errada.
|
||
|
|
Corrija-a. Um ano e bissexto se for multiplo de 4, com exceçao dos fins de seculo
|
||
|
|
(multiplos de 100), que so sao bissextos se forem multiplos de 400. Por exemplo:
|
||
|
|
1980, 1984, 2004 foram bissextos; 1800 e 1900 foram anos comuns, mas 2000 foi bissexto.
|
||
|
|
|
||
|
|
b. A funçao monthDays, para determinar o numero de dias de um mes, tambem esta errada.
|
||
|
|
Quando o mes e fevereiro, invoque a funçao anterior para determinar se o ano e
|
||
|
|
bissexto e devolva 29 dias nesse caso.
|
||
|
|
|
||
|
|
c. Corrija a funçao nextDay para devolver o dia seguinte corretamente.
|
||
|
|
"""
|
||
|
|
|
||
|
|
# This function checks if year is a leap year.
|
||
|
|
# It is wrong: 1900 was a common year!
|
||
|
|
from operator import contains
|
||
|
|
|
||
|
|
|
||
|
|
def isLeapYear(year):
|
||
|
|
if year % 100 == 0:
|
||
|
|
return year % 400 == 0
|
||
|
|
return year%4 == 0
|
||
|
|
|
||
|
|
# This function has a semantic error: February in a leap year should return 29!
|
||
|
|
# Correct it.
|
||
|
|
def monthDays(year, month):
|
||
|
|
MONTHDAYS = (0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31)
|
||
|
|
# This tuple contains the days in each month (on a common year).
|
||
|
|
# For example: MONTHDAYS[3] is the number of days in March.
|
||
|
|
days = MONTHDAYS[month]
|
||
|
|
if isLeapYear(year) and month == 2:
|
||
|
|
days += 1
|
||
|
|
return days
|
||
|
|
|
||
|
|
# This is wrong, too.
|
||
|
|
def nextDay(year, month, day):
|
||
|
|
months31 = (1, 3, 5, 7, 8, 10)
|
||
|
|
months30 = (4, 6, 9, 11)
|
||
|
|
if (month, day) == (12, 31):
|
||
|
|
year += 1
|
||
|
|
month = 1
|
||
|
|
day = 1
|
||
|
|
elif contains(months31, month) and day == 31:
|
||
|
|
month += 1
|
||
|
|
day = 1
|
||
|
|
elif contains(months30, month) and day == 30:
|
||
|
|
month += 1
|
||
|
|
day = 1
|
||
|
|
elif month == 2 and day >= 28:
|
||
|
|
if isLeapYear(year) and day == 29:
|
||
|
|
day = 1
|
||
|
|
month += 1
|
||
|
|
if not isLeapYear(year) and day == 28:
|
||
|
|
day = 1
|
||
|
|
month += 1
|
||
|
|
else:
|
||
|
|
day += 1
|
||
|
|
|
||
|
|
return year, month, day
|
||
|
|
|
||
|
|
|
||
|
|
# This is the main function
|
||
|
|
def main():
|
||
|
|
print("Was", 2017, "a leap year?", isLeapYear(2017)) # False?
|
||
|
|
print("Was", 2016, "a leap year?", isLeapYear(2016)) # True?
|
||
|
|
print("Was", 2000, "a leap year?", isLeapYear(2000)) # True?
|
||
|
|
print("Was", 1900, "a leap year?", isLeapYear(1900)) # False?
|
||
|
|
|
||
|
|
print("January 2017 had", monthDays(2017, 1), "days") # 31?
|
||
|
|
print("February 2017 had", monthDays(2017, 2), "days") # 28?
|
||
|
|
print("February 2016 had", monthDays(2016, 2), "days") # 29?
|
||
|
|
print("February 2000 had", monthDays(2000, 2), "days") # 29?
|
||
|
|
print("February 1900 had", monthDays(1900, 2), "days") # 28?
|
||
|
|
|
||
|
|
y, m, d = nextDay(2017, 1, 30)
|
||
|
|
print(y, m, d) # 2017 1 31 ?
|
||
|
|
y, m, d = nextDay(2017, 1, 31)
|
||
|
|
print(y, m, d) # 2017 2 1 ?
|
||
|
|
y, m, d = nextDay(2017, 2, 28)
|
||
|
|
print(y, m, d) # 2017 3 1 ?
|
||
|
|
y, m, d = nextDay(2016, 2, 29)
|
||
|
|
print(y, m, d) # 2016 3 1 ?
|
||
|
|
y, m, d = nextDay(2017, 12, 31)
|
||
|
|
print(y, m, d) # 2018 1 1 ?
|
||
|
|
|
||
|
|
# call the main function
|
||
|
|
main()
|