FP - Extra3 - Exercices 1 through 6 added

1ano/fp/extra3/ex01.py

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+
+# On a chessboard, positions are marked with letters between a and h for the column and a
+# number between 1 and 8 for the row. The first place on the board, a1, is black. The next
+# is white, alternating across a row. Odd rows start with black, even rows start with white.
+
+# Give a 2 character input string with a letter (a-h) and a number (1-8), print "Black" or
+# "White" indicating if the square is black or white.
+
+inputStr = 'b3'
+
+print("Black" if (
+        (inputStr[0] in ['a', 'c', 'e', 'g'] and int(inputStr[1]) % 2 == 1)
+        or (inputStr[0] in ['b', 'd', 'f', 'h'] and int(inputStr[1]) % 2 == 0)
+)
+      else "White")

1ano/fp/extra3/ex02.py

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+# Given a sequence lst, return the longest n so that
+# the first n elements equal the last n elements (with no overlapping).
+
+# Dada uma sequência lst, devolva o maior n tal que
+# os primeiros n elementos igualam os últimos n elementos (sem sobreposição).
+
+def firstEqualLast(lst):
+    if len(lst) <= 1:
+        return 0
+
+    n = 0
+    for i in range(1, len(lst)//2+1):
+        if lst[:i] == lst[len(lst)-i:]:
+            n = i
+
+    return n

1ano/fp/extra3/ex03.py

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+
+# Given a string s and a string t, return a string in which all the characters
+# of s that occur in t have been replaced by a _ sign. The comparisons are
+# case sensitive.
+
+def replaceCharactersWithUnderscores(s, t):
+    # Your code here...
+    new_str = ""
+
+    for c in s:
+        if c in t:
+            new_str += '_'
+        else:
+            new_str += c
+
+    return new_str

1ano/fp/extra3/ex04.py

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+
+# Given a string s, return the longest prefix that is repeated somewhere else in the string.
+# For example, "abcdabejf" would return "ab" as "ab" starts at the beginning of the string
+# and is repeated again later. Do not use the find method.
+
+def longestPrefixRepeated(s):
+    # Your code here...
+    longest = ""
+    
+    for i in range(1, len(s)//2+1):
+        if s[:i] in s[i:]:
+            longest = s[:i]
+
+    return longest

1ano/fp/extra3/ex05.py

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+def printStocks(stocks):
+    for stock in stocks:
+        print(f"{stock[0]:<10}{stock[1]:<19}{stock[2]:>6.2f}{stock[3]:>10.2f}{stock[4]:>10}{(stock[3]/stock[2]-1)*100:>7.1f}%")

1ano/fp/extra3/ex06.py

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+# Complete...
+stocks2 = sorted(sorted(stocks, key=lambda stock: stock[4], reverse=True), key=lambda stock: stock[0])