2023-05-16 20:14:36 +00:00
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2023-01-08 22:40:13 +00:00
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# Given a string s, return the longest prefix that is repeated somewhere else in the string.
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# For example, "abcdabejf" would return "ab" as "ab" starts at the beginning of the string
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# and is repeated again later. Do not use the find method.
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def longestPrefixRepeated(s):
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# Your code here...
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longest = ""
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2023-05-16 20:14:36 +00:00
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for i in range(1, len(s)//2+1):
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2023-01-08 22:40:13 +00:00
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if s[:i] in s[i:]:
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longest = s[:i]
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2023-05-16 20:14:36 +00:00
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return longest
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